What is the constant of variation, k, of the direct variation, y = kx, through (–3, 2)? k = –k equals negative startfraction 3 over 2 endfraction. k = –k equals negative startfraction 2 over 3 endfraction. k = k equals startfraction 2 over 3 endfraction. k = k equals startfraction 3 over 2 endfraction.

k equals negative StartFraction 2 Over 3 EndFraction

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form or

we have that

For x=-3, y=2

Find the value of the constant of proportionality k

substitute the value of y and x

The linear equation is

therefore

k equals negative StartFraction 2 Over 3 EndFraction

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation: