How to solve this problem by classifying systems of equations
3x+4y=36
-5x=35-3y

x=-32/29

Step-by-step explanation:

3x+4y=36 Equation 1

-5x+3y=35 Equation 2

Multiplying equation 1 with 3 (value before y in equation 2) and equation 2 with 4 (value before y in equation 1) we obtain equations 3 and 4 as follows

9x+12=108 equation 3

-20x+12y=140 equation 4

Subtracting equation 3 from equation 4 we obtain

-29x=32

x=-32/29

To find the value of y, we substitute the value of x into equation 2 as initially given in the equation

-5(-32/29)=35-3y

-5(-32/29)-35=-3y

so, converting firstly the mixed fractions to improper fractions and then "adding".