Find remainder
2x^3+3x^2-x+1/x+3

Step-by-step explanation

(x+3) / (2x+3) = (x +1) / (3x+2)

=> (x+3)(3x+2) = (x+1(x+3)

=>  x(3x+2)  + 3(3x+2) = x (2x3+) + 1(2x+3)

=> 3x2 +2 +9x+6=2x2+3x+3x +2x +3

=> 3x2+ 11x +6 = 2x2+5x +3

=>3x2+6+3=0

=>x=3x+=6

remainder would be 6

i think it is

step-by-step explanation:

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hope it's you