Solve the following system.
y= + 2x - 1 and 3x - y=1
the solutions are _and_

Since the coefficient of the quadratic variable is missing, I obtained it from a similar question.

The system is:

Explanation:

1. Write the system

2. Clear y from the second equation to solve by substitution

3. Substitute in the first equation and solve for x

4. Subsitute both values into the equation y= 3x - 1

that is the sum

step-by-step explanation:

there are no other answers without knowing the variables values

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.