Find the product of the complex number and its conjugate.
1 + 2i

1 - 4i
-3
5
1 + 4i

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

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x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.