Using the inspection method, what constant term must the numerator of the rational expression (x^2+8x+11)/(x+6) have so (x+6) is one of its factors? for the numerator to have (x+6) as a factor, it’s constant term must be

c=12

For the numerator to have (x+6) as a factor, it's constant term must be 12.

Step-by-step explanation:

If (x+6) is a factor, then putting x = -6 should make f (x) = 0.

x² + 8x + c

(-6)² + 8 × (-6) + c = 0

36 - 48 + c = 0

-12 + c = 0

x=4

step-by-step explanation:

answer: 1 and 3

step-by-step explanation: