Solve for x over the complex numbers.

x^2+8x+20=0

enter your answers in the boxes in standard form.

Step-by-step explanation:

A quadratic function () usually has two solutions for x. To find that solutions we have to use Bhaskara's Formula:

We have the expression:

Where,

Then, applying Bhaskara's Formula:

Remember that:

We have the first solution for x, now we have to find the second:

Then the solutions for x are:

Over the complex numbers.

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

answer: i guess 105 degrees?

step-by-step explanation: