In a certain city, 30% of the families have a mastercard, 20% have an american express card, and 25% have a visa card. eight percent of the families have both a mastercard and an american express card. twelve percent have both a visa card and a mastercard. six percent have both an american express card and a visa card. what is the probability of selecting a family that has either a visa card or an american express card?

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of these probabilities.

I am going to say that:

-The set A represents the probability that a family has a MasterCard.

-The set B represents the probability that a family has an American Express Card.

-The set C represents the probability that a family has a Visa card.

We have that

In which a represents the probability that the family only has a MasterCard, represents the probability that the family has both a MasterCard and an American Express card and represents the probability that the family has both a Master and a Visa card.

By the same logic, we also have that:

What is the probability of selecting a family that has either a Visa card or an American Express card?

This is .

We start finding the probabilities from the intersection of these sets.

Six percent have both an American Express card and a Visa card. This means that:

Twelve percent have both a Visa card and a MasterCard

Eight percent of the families have both a MasterCard and an American Express card.

25% have a Visa card

20% have an American Express card

What is the probability of selecting a family that has either a Visa card or an American Express card?

There is a 13% probability of selecting a family that has either a Visa card or an American Express card

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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