According to a government study among adults in the 25- to 34-year age group, the mean amount spent per year on reading and entertainment is $2,060. assume that the distribution of the amounts spent follows the normal distribution with a standard deviation of $495. (round your z-score computation to 2 decimal places and final answers to 2 decimal places.)

what percent of the adults spend more than $2,575 per year on reading and entertainment?

what percent spend between $2,575 and $3,300 per year on reading and entertainment?

what percent spend less than $1,225 per year on reading and entertainment?

A) P(x> 2575) = 14.92%

B) P(2575 < X<3300) = 14.32%

C)  ( P X < 1225) = 4.55%

Step-by-step explanation:

Given data:

a) P(x> 2575)

 1 - P(X<2575)

1 - P( Z< 1.04)

1 - 0.8508

0.1492

14.92%

B) P(2575 < X<3300)

P (1.04 < z< 2.51)

P(z <2.51) - P(Z<1.04)

0.994 - 0.8508 = 0.1432 = 14.32%

C) ( P X < 1225)

P ( Z< -1.69)

= 0.0455 = 4.55%

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

m

step-by-step explanation: