Which of the following inequalities is
equivalent to - 2x -- 6y > 2y - 4?
a) x < 2y+2 b) x < -4y+2
c) x> -4y + 2 d) x < 4y + 2

The answer is A

Step-by-step explanation:

-2x - (-6y) > 2y - 4

-2x + 6y > 2y - 4

-2x > 2y - 4 -6y

-2x > -4y - 4

x < 2y + 2

(Correct me if i am wrong)

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..

darn right!

step-by-step explanation:

steve kerr's sons name is let that skin in.