One number exceeds another by 6 .the sum of the numbers is 40. what are the numbers?

Let 'another number' be X

Let 'one number' be x+6

X+X+6=72

2X+6=72

2X=66

X=33

'Another number'=33

'One number'=39

answer: (1,3) and (-2,0) i think.

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions