(x-3y+ 3z=-4

2x+3y-z =15

(4x-3y- z=19

- what is the solution to the system?

x=5,y=1 and z=-2

Step-by-step explanation:

We are given that system of equation

(I equation)

 (II equation )

 (III equation )

Equation II multiply by 3 then add  with equation I

Then, we get

....(Equation IV)

Subtract equation II from equation III then we get

 (equation V)

Adding equation IV and equation V then, we get

Substitute x=5 in equation V then, we get

Substitute x=5 and y=1 in equation then, we get

Hence, the solution for the given system of equation is given by

x=5,y=1 and z=-2

chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.