Three consecutive integers have a sum of 51. find the integers.

  16, 17, 18

Step-by-step explanation:

The middle of three consecutive integers is their average value. The average of three integers is their sum (51) divided by the number of them (3).

  51/3 = 17 . . . . the middle of the three integers.

The integers are 16, 17, 18.

Maybe you're thinking an equation is necessary. The reasoning about numbers is sufficient to solve the problem, so no equation is necessary.

This sort of problem is often solved by letting the variable represent the smallest integer. If the variable is x, then the three integers are ...

  x, x+1, x+2

and their sum is ...

  (x) +(x+1) +(x+2) = 51

This gives you a 2-step equation:

  3x +3 = 51

  x+1 = 17 . . . . . divide by 3, because we can

  x = 16 . . . . . . . subtract 1; integers are 16, 17, 18

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Another way to solve this problem is the way we did it in words above. Let the variable represent the middle integer. Then the three integers are ...

  x-1, x, x+1

and their sum is ...

  (x-1) +(x) +(x+1) = 51

This gives you a 1-step equation:

  3x = 51

  x = 17 . . . . . . . . divide by 3; integers are 16, 17, 18

answer

a,b, and d

explanation

a reflection angle is more than

but less than;

an angle that measures

is a reflex angle.(true)

an angle that measures less than

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)

the answer to this question is 3/19

step-by-step explanation: