Acity planner is rerouting traffic in order to work on a stretch of road. the equation of the path of the old route can be described as y = two fifthsx − 4. what should the equation of the new route be if it is to be perpendicular to the old route and will go through point (p, q)?
y − q = negative five halves(x − p)
y − q = two fifths(x − p)
y − p = negative five halvesx − q)
y − p = two fifths(x − q)

answer:

  y − q = negative five halves(x − p)

step-by-step explanation:

the slope of a perpendicular line is the negative reciprocal of the slope of a given line:

  -1/(2/5) = -5/2

the point-slope form of the equation for a line with slope m through point (p, q) is

  y -q = m(x -p)

for your m=-5/2, this is

  y -q = -5/2(x -p)

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680