At an altitude of h feet above sea level, the air pressure, p, in inches of mercury (in hg), is given byp = 30e -3.23×10⁻⁵*han unpressurized seaplane takes off at an angle of 35° to the horizontal and a speed of 80 mph. what is the rate of change of pressure in the plane with respect to time at take-off, in inches of mercury per second?

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

answer: check all that apply, where the options?

step-by-step explanation:

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step-by-step explanation: