Trains headed for destination a arrive at the train station at 15-minute intervals starting at 7 a. m., whereas trains headed for destination b arrive at 15-minute intervals starting at 7: 05 a. m. (a) if a certain passenger arrives at the station at a time uniformly distributed between 7 and 8 a. m. and then gets on the first train that arrives, what proportion of time does he or she go to destination a

  2/3

Step-by-step explanation:

In the 5-minute interval between 7:00 and 7:05, a train to B is the first to arrive. In the 10-minute interval between 7:05 and 7:15, a train to A is the first to arrive. That is, in any 15-minute interval, the probability is 10/15 = 2/3 that a train to A is the first to arrive.

The 1-hour interval between 7 A.M. and 8 A.M. is an integer number of such intervals, so ...

  2/3 of the time, he or she will go to destination A.

reduce the friction between its moving parts

step-by-step explanation:

in fact, by reducing the friction between the moving parts of the machine, it is possible to reduce the energy wasted due to this friction; therefore, more input energy is converted into useful work, and this will improve the efficiency of the machine.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?