Ifind a bowl of colored christmas candies (only red and green) that were hidden from me in the house one day. i quickly grab a handful before being caught. before shoving them into my mouth to get rid of the evidence, i notice that i have selected 5 red candies and no green ones. let's say there were 6 green and 7 red candies in the bowl before my discovery. what is the probability of this event occurring?

The probability of the occurring the event is 0.01632 approximately

Step-by-step explanation:

Consider the provided information.

We have selected 5 red candies and no green ones. Let's say there were 6 green and 7 red candies in the bowl before discovery.

Therefore the total number of candies are 6+7=13

I have selected 5 red candies out of 7 red candies.

Thus, the probability of selecting 5 red candies and no green candies is:

Hence, the probability of the occurring the event is 0.01632 approximately

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.