Apair of equations is shown below:

y = 8t − 9
y = 4t − 1

part a: explain how you will solve the pair of equations by substitution or elimination. show all the steps and write the solution. (5 points)

part b: if the two equations are graphed, at what point will the lines representing the two equations intersect? explain your answer. (5 points)

Part A: t = 2 and y = 7

Part B: Point of intersection is (2,7)

Step-by-step explanation:

Part A: We are given the pair of equations shown below:

y = 8t - 9 (1)

y = 4t - 1 (2)

We can solve those equations by the elimination method.

We have from [equation (1) - equation (2)], 0 = 4t - 8

⇒ t = 2

Therefore, from equation (2), we get y = 4 ×2 - 1 = 7

Hence, t = 2 and y = 7 is the solution of the given pair of equations.

Part B: As equation (1) and equation (2) are two straight lines, so their solution gives the point of intersection of those two lines on the graph.

Therefore, if we plot t along the X-axis and y along the Y-axis then the point of intersection will be (2,7) point. (Answer)

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

x^3-4x^2+3x-2/x^2+1

step-by-step explanation:

factor the numerator and denominator and cancel the common factors