What is the slope and equation of a line that is perpendicular to the y-axis passing through (-5,-3)?

Slope is m=0

Step-by-step explanation:

The slope of any line that is perpendicular to the y-axis is zero.

The reason is that any line that is perpendicular to the y-axis is also parallel to the x-axis and the slope of the x-axis is zero.

The equation of any line perpendicular to the y-axis is and passes through (a,b) is y=b.

The given point is (-5,-3) hence the required equation is

5.6%

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116