Aball is thrown upward from the top of a building. the ball's height above the ground after t seconds is given by the function: h(t) = -16t^2+48t+32.
a. what is the initial height (i. e. the height of the building)?
b. how high did the ball go?
c. when does the ball hit the ground?

A) The initial height is 32

B) The higher height that the ball gets is 68

C) at

Step-by-step explanation:

A) For this part you only have to evaluate the function in t=0, this is:

B) To obtain the higher height you have to find the maximum value that reaches the function . For  this we can use the first derivative rule.

Then we have:

How we only have one extreme point we assume that this is a maximum, and this point is in the value , this is . Then, evaluate the function in

we have

C) In this case we need to know when the function is 0. For this we can use the quadratic formula, with

a

step-by-step explanation:

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )