Ahusband and wife discover that there is a 12% probability of their passing on a hereditary disease to any of their children. if they plan to have three children, what is the probability of the event that at least one child will inherit the disease?

0.318528

Step-by-step explanation

Let x be the binomial variable (for success) that represents the children that have a hereditary disease

with parameter p = 0.12  n= 3

Using binomial , we have

Required probability :-

Hence, the probability of the event that at least one child will inherit the disease =0.318528

1) is right

step-by-step explanation: