Acar leaving a stop sign accelerates constantly from a speed of 0 feet per second to reach a speed of 44 feet per second. the distance of the car from the stop sign, d d , in feet, at time t t , in seconds, can be found using the equation d=1.1 t 2 d=1.1t2 . what is the average speed of the car, in feet per second, between t=2 t=2 and t=5 t=5 ? 5.5 6.6 7.7 8.5

the difference between a number and 5 is -2.

step-by-step explanation:

notice that the equation you are given has -2 (negative 2) on the right side, not 2. when you subtract 5 from a number n, you are finding the difference between the number and 5.

the difference between a number and 5 is -2.

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step-by-step explanation:

maybe showing the graph would

step-by-step explanation:

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