Find the slope-intercept form of the line whose slope s 5 and that passes through the point (-6,10)

The slope-intercept form of the line whose slope is 5 and that passes through the point (-6,10) is y = 5x + 40

Solution:

We have been asked to find the slope intercept form for the point (-6,10) and slope 5.

The slope intercept form of a line is given in the following way:

y = mx + c --eq1

Where m is the slope of the line and c is the y intercept of the line.

To find c we have to substitute the x and y coordinates in eq1 along with value of the slope ‘m’ of the line.

Now the equation becomes:

Now solving for c we get:

10 = -30 + c

c = 40.

So now we to get the slope intercept for we have to substitute the value of m and c in equation 1

This gives us:

y = 5x + 40

Thus the slope intercept form of the line is y = 5x + 40

rectangle: 9 1/8 x 4 1/9 = 37 37/72in

parallelogram: b times h= 10.3 x 6.2 = 63.86

trapezoid: a+b/2 times h= 42.5

volume of prism: l times w times h= 36

answer: i believe its b. if you sound out the sentences that sounds wrong.