Aprocess is normally distributed and in control, with known mean and variance, and the usual three-sigma limits are used on the control chart, so that the probability of a single point plotting outside the control limits when the process is in control is 0.0027. suppose that this chart is being used in phase i and the averages from a set of m samples or subgroups from this process are plotted on this chart. what is the probability that at least one of the averages will plot outside the control limits when m = 5? discuss the results that you have obtained.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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i need a diagram

step-by-step explanation:

no

step-by-step explanation:

left be aligning the decimal points is required to not required see the number of digits to the right

the answer to your question is c.)   volcanoes built the mountains and earthquakes tore them down.

step-by-step explanation: