The director of a museum recorded the number of students and adult chaperones in several school groups visiting the museum. she organized
the data in a scatter plot, where x represents the number of students and y represents the number of adult chaperones. then she used a
graphing tool to find the equation of the line of best fit:
y = 0.123x + 5.397
based on the line of best fit, approximately how many students are predicted to be in a school group with 20 adult chaperones?

Ok here we go ..there are plenty of ways to solve such math problems but we will go for the smartest and easiest ..5x+2y=7  -2x+6y=9we rearrange them into the following ..by multiplying the 1st equation by 2 it becomes 10x + 4y = 14we rearrange it and so it becomes 10x = 14 - 4yas for the second equation we multiply it by 5 and rearrange it so it becomes as to the following ..-10x + 30y = 45rearranging so 10x = 30y -45now 10x equals both 14 - 4y and 30y -45so   14 - 4y = 30y -4531 = 26yy= 31/26 = 1.19 or around 1.2so by now we can calculate x easily as  -2x+6y=9so 2x = 6y -9 = 6 * 31/26 - 9 = -1.84  then x = - 0.92 or around -0.9best luck!