Jean stocked her aquarium with 36 fresh-water fish, which cost $212. the male fish cost $5 each, while the female fish cost $7 each. find the number of male fish (x) and the number of female fish (y).

Male Fish = 20

Female Fish = 16

Step-by-step explanation:

Let number of male fish be x and number of female fish be y

There are 36 fishes in total, so we can write:

x + y = 36

or

x = 36 - y

Also, male fish (x) cost 5 each and female fish (y) cost 7 each totalling $212, so we can write:

5x + 7y = 212

Now, we can put 1st equation in 2nd equation and get an equation in "y" and solve for y first:

We know x = 36 - y, so

x = 36 - 16

x = 20

Thus,

there are

20 Male fishes & 16 female fishes in the aquarium

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

answer: 1+1

step-by-step explanation: 1+1 is at least 2