Drag each system of equations to the correct location on the table.
classify each system of equations as having a single solution, no solution, or infinite solutions.
y=5-2x
4x + 2y = 10
x = 26 - 3y
2x + y = 22
5x + 4y = 6
10x - 2y = 7
x + 2y = 3
4x + 8y = 15
3x + 4y = 17
6x = 10y - 39
x + 5y = 24
5x = 12-y
single solution
no solution
infinite solutions

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.

add -60 to 120 which will result in : 2x+3y=180

then subtract 2x: 3y=-2x+180

lastly, divide by 2: y= -2/3x+60

hope this is the answer you're looking for: )