Determine the type and number of solutions of x^2 + 2x + 3 = 0.
one real solution
two imaginary solutions
two real solutions

The equation has 2 imaginary solutions

Step-by-step explanation:

x² + 2x + 3 = 0

D = b² - 4ac

= 2² - 4(1)(3)

= -8

< 0

D>0 (2 real solutions)

D=0 (1 real solution)

D<0 (2 imaginary or no real

solutions)

(Correct me if i am wrong)

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.