The length of a rectangle is
2m

longer than its width.
if the perimeter of the rectangle is
48m

, find its length and width.

Perimeter is found by multiplying the length by 2 and adding it to the width multiplied by 2.

The formula is P = 2L + 2W

The length is 2m more than the width, which would be written as W +2

Now the formula is P = 2(W+2) + 2W

Replace P with the given perimeter and solve:

48 = 2(W+2) +2W

Simplify:

48 = 2W +4 + 2W

48 = 4W +4

Subtract 4 from both sides:

44 = 4W

Divide both sides by 4:

W = 11

Now you have the width solve for the length.

Length = Width +2 = 11 + 2 = 13

Check: 2(11) + 2(13) = 22 + 26 = 48

This works out to be true.

Length = 13 m

Width = 11 m

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

move it to the other side

step-by-step explanation: