1. find the value of x and y so that nr mo.
2. find m zmsn.
(9y + 18
3. m zebf = 3x + 10, m zdbe = x, and bdibf find the value of x.
4. if m zebf = 7y - 3 and m zfbc = 3y + 3, find the value of y so
that be ibc.
5. find the value of x, m zpqs, and m zsqr.
klex
6. find the value of y, m zrpt, and m ztpw.
(2y + 5)
glenme geometry

The answer to your question is b’(16,14)

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%