An aerospace company has submitted bids on two separate federal government defense contracts. the company president believes that there is a 40% probability of winning the first contract. if they win the first contract, the probability of winning the second is 72%. however, if they lose the first contract, the president thinks that the probability of winning the second contract decreases to 54%.a. what is the probability that they win both contracts? probability =b. what is the probability that they lose both contracts? probability =c. what is the probability that they win only one contract? probability =

1)28.8%

2)28.8%

3)43.6%

Step-by-step explanation:

1))Probability of wining both = Probability that first contract is won* Probability that second contract is won = 0.4 * 0.72 = 0.288 = 28.8%

2)Probability of losing = 1 - Probability of winning

Probability that they will lose both contracts = Probability that first contract is lost * Probability that second contract is lost = (1 - 40/100) * (1 - 54/100) = 0.276 = 27.6%

3)Probability that any one is won = 1 - both contracts are won - both contracts are lost = 1 - 0.276 - 0.288 = 0.436 = 43.6%

answer: sorry i can't you.

step-by-step explanation:

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation: