The quality control manager at a computer manufacturing company believes that the mean life of a computer is 83 months, with a standard deviation of 9 months. if he is correct, what is the probability that the mean of a sample of 78 computers would be less than 82.06 months? round your answer to four decimal places.

0.1788

Step-by-step explanation:

As per given , we have

Let x be the random variable that represents the life of a computer.

Sample size : n= 78

Then, the z-score corresponds to x= 82.06 will be :-

[∵ ]

Required probability ( using standard z-value table ) :-

Hence, the probability that the mean of a sample of 78 computers would be less than 82.06 months = 0.1788

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

answer: asdfghjkl,mnbv

step-by-step explanation: