Two buses leave towns 948 miles apart at the same time and travel toward each other. one bus travels 10 mi h slower than the other. if they meet in 6 hours, what is the rate of each bus?

Use a d=rt table, find x, and plug it in for the part you need. 74 & 84

Step-by-step explanation:

Create a chart for the 2 buses that shows the distance, rate, & time. Calculate the distance by multiplying the rate and time.

x is the rate of speed of the faster bus

Bus 1: D (6x) = r (x) × t (6 hrs)

Bus 2: D (6x-60) = r (x-10) × t (6 hrs)

We also know the total distance traveled was 948 miles. So 6x-60+6x=948.

Then we combine like terms.

12x-60=948

Now isolate the x term by adding 60 to both sides.

12x=1008

Divide both sides by 12 to isolate the x.

x=84

Finally, plug the x back in to the rates to determine the rate of the buses.

Bus 1 - 84 mph

Bus 2 - 74 mph

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk