Aconductor possesses a positive charge of 3.2x 10-19 c. how many electron does it have in excess or deficit (e = 1.60 x 10-19c)

The no of electrons it have in deficit=1.60

Given:

Charge possessed by a conductor =

Charge of an electron=

To find:

Amount of electrons in excess or deficit

Step by Step Explanation:

Solution;

Formula used for calculating electrons in excess or deficit is given as

Electrons in excess or deficit= Normal electron charge- Charge of the conductor

Also we know Charge of Conductor and Electron charge  

Substitute these values in the above equation we get

Electrons in excess or deficit=

= -1.60

Result:

Hence, it has a deficit of 1.60 electrons.

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5