The expression log (x^6y^3/z^9) can be written in the form alog(x)+blog(y)+clog(z) where
a=
b=
c=

A = 6

B = 3

C = 9

Step-by-step explanation:

We start by using repeatedly the product rule of logarithms that converts the logarithm of a product of two factors into the addition of logarithms: :

At this point we use on each term of the expression we found above, the power rule of logarithms that states:

This gives as:

Therefore, the coefficients A, B, and C requested are:

A = 6

B = 3

C = 9

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

168

step-by-step explanation:

i am pretty sure that the answer is 168