Shaun drew δlmn, in which m∠lmn = 90°. he then drew δpqr, which was a dilation of δlmn by a scale factor of 3 from the center of dilation at point m. which of these can be used to prove δlmn ~ δpqr by the aa similarity postulate?

segment lm = 3segment pq; this can be confirmed translating point p to point l.
segment mn = 3segment qr; this can be confirmed translating point r to point n.
m∠p ≅ m∠n; this can be confirmed by translating point p to point n.
m∠r ≅ m∠n; this can be confirmed by translating point r to point n.

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)

i have no clue what you just said. write a question in english?

1. 180°. the sum of the interior angles of a triangle is 180°, for the equilateral triangle that it has three equals side is 60°+60°+60°=180°.

2. 60°. each interior angle of a equilateral triangle is 60°

3. 120°. the measure of ∠m is 120°, the sum of the angles ∠m and ∠n is equal to 180°. so, in order to find the measure of ∠m, we have ∠m+∠n=180° > ∠m=180°-∠n > ∠m=180°-60°=120°.

4. 360°. the sum of the exterior angles of an equilateral triangle is ∠m+∠r+∠x=120°+120°+120°=360°. the exterior angles of any triangle always add 360°.

umm im not really sure because i never had to do this

step-by-step explanation: