Two planes simultaneously left the washington and la and headed towards each other. the distance between the cities is 2700 miles. after they flied for 2 hours, they have not met each other yet, and distance between them was still 500 miles. what is the speed of each plane, if the one from la was 100 mph faster?

a = 500 miles per hour

b = a + 100= 600 miles per hour

Step-by-step explanation:

Let a be speed of plane flying from Washington

distance moved after 2 hrs =2a

Let b be speed of plane flying from LA

distance moved after 2 hrs =2b

2a + 2b + 500 = 2700

2a + 2b = 2200 1

b = a + 100 (plane from LA is faster)

2a + 2(a+100) = 2200

4a = 2000

a = 500 miles per hour

b = a + 100= 600 miles per hour

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

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