Kiana wants to write equations in the form y=mx+b for the lines passing through point p that are parallel and perpendicular to line q. first she finds the slope of line q and line r to be 12 and the slope of line s to be −2. point p is located at (−3,2). which step could be used to find the y-intercepts?

i dont know

step-by-step explanation:

the translated point is (5,2)

the area of a triangle is determined by the formula: base x height * 1/2

you'll need to assign a base to the triangle. based on the vertices given, the simplest base would be the line segment from (-2,1) to (2,1). the distance between any two numbers is found by just subtracting them. here, you should subtract the x values to find the distance of this side.

2 - (-2) = 4.

so the distance (aka the length of the base) is 4. the height of the triangle is the distance between the base and the highest point on the triangle which is (3,4). we should subtract the y values this time to find the height/distance.

4 - 1 = 3

so the height is 3.

base = 4

height = 3

hope this if needed hmu