The equation of like ef is y= -1/2x + 6. write an equation of a line parallel to line ef in slope intercept form that contains point (0,-2)

  y = -1/2x -2

Step-by-step explanation:

The slope-intercept form of the equation for a line is ...

  y = mx + b

Comparing this to the equation you are given, you find that the given equation describes a line with a slope of -1/2 and a y-intercept of +6. The parallel line will have the same slope, so m=-1/2.

The given point is the y-intercept of the line you want, so you can use that y-value directly as the "b" in the equation you want:

  y = -1/2x -2

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation:

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).