Add (2+3i) + (4-6i) i need i have to show all work

ANSWER:

The answer on solving the given equation (2+3i) + (4-6i) is 6-3i.

SOLUTION:

We have been asked to add (2+3i) + (4-6i).  

‘i’ is a complex number or can be called an imaginary number, it can be said to have a value of which is non-existent. But has a value of -1.

So, in the given equation we just have to add the given terms.

Therefore, the answer becomes:

=2 + 3i + 4 - 6i

Add like terms we get,

=6 - 3i

The answer on solving the given equation is 6-3i.

the correct answer is the second option

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?