Aline that includes the points (6,h) and (7,−10) has a slope of −7. what is the value of h ?

-3

Step-by-step explanation:

You can use to find the slope of a line going through and .

I like to line up the points and subtract vertically. Then put 2nd difference over 1st difference.

(6,h)

minus

(7,-10)

------------

-1     h-(-10)

This also said to be equal to -7:

Multiply -1 on both sides:

Subtract 10 on both sides:

[texh=-3[/tex]

So if h=-3 then the slope of the line going through (6,h) and (7,-10) is -7.

Let's test it:

(6,-3)

minus

(7,-10)

----------

-1  7

So the slope is 7/-1=-7. This is the intended goal.

The check is good.

the answer is h= -3

Step-by-step explanation:

add 7 to -10 to find the value of h

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

yes

step-by-step explanation: