Find the vertex form of a parabola with a vertex of (-2, 12)
that passes through (-4, 0)

y = - 3(x + 2)² + 12

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 2, 12), thus

y = a(x + 2)² + 12

To find a substitute (- 4, 0) into the equation

0 = a(- 2)² + 12, that is

4a + 12 = 0 ( subtract 12 from both sides )

4a = - 12 ( divide both sides by 4 )

a = - 3

y = - 3(x + 2)² + 12 ← equation in vertex form

x= -3

step-by-step explanation:

step 1: simplify brackets

4 - x - 1 = 6

step 2: simpilfy

3 - x = 6

step 3: subtract 3 from both sides

-x = 6 - 3

step 4: simpilfy 6 - 3

-x = 3

step 5: multiply both sides by -1

x = -3

d. it is a convex pentagon because it has five sides and none of the sides would extend into the inside of the polygon.

step-by-step explanation: