Does (6,3) make the inequality 16x+ 20y≤5 true?

No, it is false.

Step-by-step explanation:

Because you have 6 on the left and 3 on the right, 6 is in place of x while 3 is in place of y.

Because the variables are crammed together with the actual numbers, you multiply them. 6*16=96 and 3*20=60. 60+96=156.

It is pretty clear at this point that 156 is not less than or equal to 5, so the statement is false.

20

step-by-step explanation:

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17