To a box that contained 30 pencils 10 out of which were red several more non-red pencils were added. now 25% of all pencils in this box are red. how many non-red pencils were added to the box?

The Amount of Non-red pencil which were added to the box = 10

Step-by-step explanation:

Given as :

The number of pencils in a box = 30

The number of red pencils in a box out of 30 = 10

So , the number of Non-red pencils = 30 - 10 = 20

Again let the number of Non-red pencils which added further = x

So, now the amount of total pencil get increase to (30+x)

Among (30+x) pencils in box,25% of them are red ,

I.e The number of red pencils in a box out of (30+x) = 25% of (30+x)

And the number of Non-red pencils = 20 + x

SO, according to question

25% of (30+x) + (20+x) = (30+x)

Or,   (20+x) = (30+x) - (25% of (30+x))

Or,   20+x = (30+x) [ 1 -(]

Or,    20+x  = (30+x) (

Or,    80+4x = 90+3x

or       4x - 3x = 90-80

Or,   x = 10

Hence the number of Non-Red pencils in the box which added further = 10  Answer

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.