Construct a confidence interval of the population proportion at the given level if confidence ×= 180, n=300, 90% confidence
the 90% confidence interval is

What is the missing step in this proof ?

Use the quadratic formula to solve the equation. if necessary, round to the nearest hundredth. x^2 - 23 = 10x a. -1.93, 11.93 b. 1.93, -11.93 c. 1.93, 11.93 d. -1.93, -11.93

If (x) = 3х - 2 and g(x) = 2х+ 1, find (f- g)(x). оа. х- з ов. 3-х ос. 5x - 1 od. 5x - з