Ill give brainliest explain the answer too

(x^2+2x+1)

2x^2+2x+3-x^2-2x-1=

x^2+2

The Answer is: i, where "i" is an imaginary number, the square root of negative 1.

Step-by-step explanation:

(2x^2 + 2x + 3) - (x^2 + 2x + 1) =

2x^2 + 2x + 3 - x^2 - 2x - 1 =

2x^2 + 2 =

2x^2 = -2

x^2 = -2/2

x^2 = -1

x = Sqrt -1 = i, where "i" is an imaginary number, the square root of negative 1.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

47 - 90 = 43

43 - 180 = x

x = 137