The lengths of two sides of a triangle are 8 feet and 12 feet. find the range of the possible lengths for the third side

Step-by-step explanation:

The longest side of a triangle must be less than the sum of the shorter sides.

If 8 and 12 are the shorter sides, and c is the longest side, then:

c < 8 + 12

c < 20

If c and 8 are the shorter sides, and 12 is the longest side then:

12 < c + 8

4 < c

The range of possible lengths for the third side is:

4 < c < 20

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116