The sum of three consecutive integers is 21 larger
than twice the smallest integer. find the integers.

The consecutive integers are:

18, 19, 20

Step-by-step explanation:

Let the three consecutive integers be:

x

x+ 1

x+2

Now according to given conditions:

x + x+1 +x + 2 = 21 + 2x

Adding like terms:

3x + 3 = 21 + 2x

Taking terms with x on left side and constants on right side

3x - 2x = 21 - 3   (Sign of transferred terms will be changed)

x = 18

So the consecutive terms become:

x = 18

x + 1 = 19

x + 2= 20

I hope it will help you!

18.75 gallons

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180