Aradioactive substance decays exponentially. a scientist begins (t=0) with 200 milligrams of a radioactive substance, where the variable t t represents time (in hours). after 24 hours, 100 mg of the substance remain. how many milligrams will remain at t= 37 hours?

34.35 mg.

Step-by-step explanation:

We have been given that a radioactive substance decays exponentially. A scientist begins (t=0) with 200 milligrams of a radioactive substance, where the variable t represents time (in hours). After 24 hours, 100 mg of the substance remain.

We know that an exponential decay function is in form , where,

A(t) = Final amount,

a = Initial value,

b = Decay rate,

t = time.

For our problem initial value (a) is 200, final amount is 100 and time is 24.

Let us solve for b.

So our required function is .

Substitute in above equation:

Therefore, 34.35 milligrams of substance will remain after 37 hours.

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)