Quadrilateral pqrs is shown.

there is a quadrilateral pqrs in which the length of side pq is 6b, the length of side qr is 4a+1, the length of side rs is 11b-10, and the length of side ps is 2a+9. the measure of angle pqr is (6x+13) degrees and the measure of angle psr is (7x-5) degrees.

what must the values of a and b be for pqrs to be a parallelogram?

The value of a = 8  and b= 2  for PQRS to be a parallelogram  

Step-by-step explanation:

Given as :

Quadrilateral PQRS having side PQ , QR , RS , PS

The measure of side is

PQ = 6b ,           QR = 4a + 1

RS =  11b - 10    , PS = 2a + 9

The measure of angle PQR is  (6x + 13)    And   PSR is  (7x - 5)

The parallelogram become quadrilateral  when its opposite sides is parallel and equal

I.e PQ = RS            And           QR = PS

Or 6b = (11b - 10)    

Or, 10 = 11b - 6b      

Or, 5b = 10

∴  b= = 2      or, b = 2

Again ∵  QR = PS

So,  4a + 1 = 2a + 9

Or,   4a - 2a = 9 - 1

∴   a = 8

Hence the value of a = 8  and b= 2  for PQRS to be a parallelogram  Answer

need more information

step-by-step explanation:

step-by-step explanation:

a'(12.5,11.25)

slope=(y1-y2)/(x1-x2)